Find the remainder when x^{3}+3 x^{2}+3 | vedclass

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Question

We have $p ( x )= x ^{3}+3 x ^{2}+3 x +1$ and zero of $x +\pi=(-\pi)$

$[\because x+\pi=0 \Rightarrow x=-\pi]$

$	herefore$      $

Vedclass · Accepted Answer

$-\pi^{3}+3 \pi^{2}-3 \pi+1$

Vedclass · Answer

We have $p ( x )= x ^{3}+3 x ^{2}+3 x +1$ and zero of $x +\pi=(-\pi)$

$[\because x+\pi=0 \Rightarrow x=-\pi]$

$	herefore$      $p (-\pi)=(-5)^{3}+3(-\pi)^{2}+3(-\pi)+1$

$=-\pi^{3}+3\left(\pi^{2}ight)+(-3 \pi)+1=-\pi^{3}+3 \pi^{2}-3 \pi+1$

Thus, the required remainder is $-\pi^{3}+3 \pi^{2}-3 \pi+1$.

Find the remainder when $x^{3}+3 x^{2}+3 x+1$ is divided by $x+\pi$

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